Question

if Alfa and bita are the zeroes of the polynomial p(x)= x²+2x+3 the value of 1/Alfa+1/bita is​

Answer 1

Step-by-step explanation:

$If \alpha \: \: and \: \: \beta \: are \: the \: zeros \: of \: the \: given \: \\ polynomial \: \: \: then \\ \alpha + \beta = - 2 \\ \alpha \beta = 3 \\ \\ \frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ \alpha + \beta }{ \alpha \beta } = \frac{ - 2}{3} \\ \\ \\ Hope \: it \: will \: help \: you \:$

Answer 2

Answer:

Step-by-step explanation:

α and β are the two zeroes of p(x)     (GIVEN)

p(x) = x²+2x+3       (GIVEN)

We have to find 1/α + 1/β

If we take out the LCM of α and β , then denominator = αβ

and numerator=α+β  our equation will be  α+β÷αβ

We have learnt that α+β= -b÷a     and    αβ = c÷a

  And from p(x) , a=1 b=2 c=3

After putting the values of a and b in the equation above your answer will be -2÷3