Math, asked by eshaafsal2004, 10 months ago

If alfa and bita are the zeros of the polynomial 2x^2-7x+3.evaluate:
1.alfa square +bita square
2.alfa/bita+bita/alfa
3.alfa cube+bita cube
5.1/alfa cube +1/bita cube
6.alfa square /bita+ bita square /alfa

Answers

Answered by sansanwalkajal4
1

Step-by-step explanation:

FIRST OF ALL FIND THE ROOTS OF THE EQUATION

ALFA = 3 ; BEETA = 1/2

NOW,

1. ALFA SQUARE + BEETA SQUARE = 9 + 1/4 = 37/4

2. ALFA/BEETA+BEETA/ALFA = 37/6

3. ALFA CUBE + BEETA CUBE = 27+1/8= 217/8

5. 1/ALFA CUBE +1/BEETA CUBE = 217/27

6. ALFA SQUARE/BEETA+BEETA SQUARE/ALFA = 217/12

HOPE IT HELPS

MARK AS BRAINLIEST ..

Answered by umabhowmick1234
10

Answer:

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Step-by-step explanation:

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