If alfa and bita are the zeros of the polynomial 2x^2-7x+3.evaluate:
1.alfa square +bita square
2.alfa/bita+bita/alfa
3.alfa cube+bita cube
5.1/alfa cube +1/bita cube
6.alfa square /bita+ bita square /alfa
Answers
Answered by
1
Step-by-step explanation:
FIRST OF ALL FIND THE ROOTS OF THE EQUATION
ALFA = 3 ; BEETA = 1/2
NOW,
1. ALFA SQUARE + BEETA SQUARE = 9 + 1/4 = 37/4
2. ALFA/BEETA+BEETA/ALFA = 37/6
3. ALFA CUBE + BEETA CUBE = 27+1/8= 217/8
5. 1/ALFA CUBE +1/BEETA CUBE = 217/27
6. ALFA SQUARE/BEETA+BEETA SQUARE/ALFA = 217/12
HOPE IT HELPS
MARK AS BRAINLIEST ..
Answered by
10
Answer:
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Step-by-step explanation:
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