if alfa and bitta are the zeroes of polynomial 2ysquare + 7y +5 write values of alfa +bitta +alfa bitta
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Given:
We have been given that a and b are the zeroes of the polynomial 2y^2 + 7y + 5.
To Find:
We need to find the value of a + b + ab.
Solution:
We have been given a polynomial 2y^2 + 7y + 5.
Here, a = 2, b = 7 and c = 5.
As it is given that a and b are two zeroes,
So, sum of zeroes(a + b)
= -b/a
= -7/2___(1)
Product of zeroes(ab)
= c/a
= 5/2___(2)
Now we need to find the value of a + b + ab,
So we have,
a + b + ab = (a + b) + ab
Substituting the values from equation 1 and 2, we get,
(-7/2) + (5/2)
= (-7 + 5)/2
= -2/2
= -1
Therefore, the value of a + b + ab is -1.
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