If alfa and bitta are zeroes of the polynomial x^2+2x+1 then 1/alfa + 1/ bitta is :
a) -2
b) 2
c) 0
d) 1
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- Option a) -2 is the correct answer
Step-by-step explanation:
Given:
- Polynomial P(x) = x² + 2x + 1
- α and β are two zeroes of the polynomial P(x)
To find:
The value of (1/α) + (1/β)
- From the polynomial P(x)
We get, a = 1, b = 2, and c = 1
Now,
(1/α) + (1/β)
= (β + α)/αβ
[∵ by taking LCM = αβ]
Here,
(β + α) = Sum of the zeroes
And αβ = product of zeroes
So,
Sum of zeroes = ( - coefficient of x)/(coefficient of x²) = (-b)/a = -2/1 = (-2)
And
Product of zeroes = (constant term)/(coefficient of x²) = c/a = 1/1 = 1
Now,
Putting the values in = (β + α)/αβ
= (-2)/1 = -2
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