Question

If Alfa and ßita are zeroes of the polynomial 2x²+3x-6, then find the value .

alfa - ßita ​

Answer 1

Answer:

3.77 Or 3.78

Step-by-step explanation:

$2x {}^{2} + 3x - 6 \\ after \: factorization \: \\ we \: get \: \alpha \: is \: equal \: to \: \frac{ - 3 + \sqrt{57} }{4} \\ and \ \: \beta \: is \: equal \: to \: \frac{ - 3 - \sqrt{57} }{4 } \\ now \: \\ \alpha + \beta = \frac{ - 3 + \sqrt{57} }{4} - ( \frac{ - 3 - \sqrt{57} }{4}) \\ \: \: \: \: = \frac{ - 3 + \sqrt{57 } + 3 + \sqrt{57} }{4} \\ \: \: \: = \frac{2 \sqrt{57} }{4 } \\ = \frac{ \sqrt{57} }{2} \\ = 3.77 \: or \: 3.78$