Math, asked by vaishnavib075, 18 days ago

If alfa,beeta are the zeroes of the Polynomial, 5√5x² + 20x+3√5, find (alpha×beeta)2

Answers

Answered by datars211gmilcom

0

Answer:

since, à and ß are zero given polynomial

so, à.ß=c/a

=3√5/5√5

=3/5

(à.ß)²=(3/5)²=9/25

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