If alfa _ beta, alfa and alfa + beta are the zeroes of the polynomial of (x)=x cube _ 12xsquare +39x + k then find the value of k
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Let α= a-d
β =a
γ=a+d
So,
α+β+γ=12
=》(a-d)+(a)+(a+d)=12
=》3a=12
=》a=4
αβ+βγ+αγ=39
(a-d)a+(a+d)a+(a-d)(a+d)=39
Note:-
Please solve it, then you will get-
d=+3 or -3
Hence,
1》α=a-d
or,
4-
=1
or,
4-(-3)
=7
2》β=4
3》γ=》4+3=7
or,
4+(-3)
=1
Hence,
αβγ= -k
.•.-k=1 × 4 × 7
So,
k = -28
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