Question

if alfa^beta are the zeroes of the equation 6x^2+x-2, find alfa/beta+beta /Alfa.....
plzzz fast

Answer 1

A/B + B/A = ((A+B)^2 - 2 AB)/AB , where A, B are root of equation

A+B = —b/a = -1/6 ,AB = c/a =-2/6 = -1/3 , put these value in above equation

= (1/36 +2/3)/-1/3 = - 25/12

Answer 2

alpha/beta + beta/ alpha

= alpha.alpha + beta.beta) / alpha beta

= ( alpha + beta)^2 - 2 alpha beta )/ alpha beta

AS alpha + beta = -1/6

alpha beta = -2/6 = -1/3

So (-1/6)^2 - 2×-1/3 ) / -1/3

= 1/36 + 2/3 ) / -1/3

= -( 25)×3/36

= -25/12