If alfa beta are zeros of polynomial x2+x+1. Then find the sum of thier reciprocals
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Answered by
0
It's easy
To find-. 1/alpha+1/beta
If u take its LCM, U WIL FIND u get alpha + beta/alpha*beta
Now u know that alpha+beta= -b\a and alpha*beta is c/a
To find-. 1/alpha+1/beta
If u take its LCM, U WIL FIND u get alpha + beta/alpha*beta
Now u know that alpha+beta= -b\a and alpha*beta is c/a
Answered by
0
Heya !!!
X² + X + 1
Here,
A = 1 , B = 1 and C = 1
Sum of zeroes = -B/A
Alpha + Beta = -1 -------(1)
And,
Product of zeroes = C/A
Alpha × Beta = 1 --------(2)
Therefore,
1/ Alpha + 1/Beta
=> Beta + Alpha / Alpha × Beta
=> -1/1
=> -1
★ HOPE IT WILL HELP YOU ★
X² + X + 1
Here,
A = 1 , B = 1 and C = 1
Sum of zeroes = -B/A
Alpha + Beta = -1 -------(1)
And,
Product of zeroes = C/A
Alpha × Beta = 1 --------(2)
Therefore,
1/ Alpha + 1/Beta
=> Beta + Alpha / Alpha × Beta
=> -1/1
=> -1
★ HOPE IT WILL HELP YOU ★
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