Question

If alfa beta Gama are zeros of 6x^2+5x^2 +4x+3,then alfa^-1+beta^-1+gama^-1is​

Answer 1

Answer:

alpha + beta + gama = -b/a = -5/6

alpha × beta + beta × gama + alpha × gama = c/a = 4/6

alpha × beta × gama = -d/a = -3/6

1/alpha + 1/ beta +1/ gama =

alpha×beta + beta×gama + alpha×gama/alpha×beta× gama

4/6÷-3/6

4/6×6/-3 = 4/-3

Hope this helps you if so please mark my answer as brainliest

Answer 2

are janie kiara hun aa n mere question p..