Question

if alfa,bita and gema are the zeroes of polynomial p(x) such that (alfa+beta+gema)=3 (alfa×beta+beta×gema+ gema×alfa)=-10and (alfa×beta×gema)=-24 then find the p(x)​

Answer 1

Answer:k(x³-3x²-10x+24)

Step-by-step explanation:

If alpha(a), beta(b) gamma(g) are zeros of a cubic polynomial p(x) then p(x) = k(x³ - (a+b+g) + (ab+bg+ga) - (abg))

Where k is any real number(constant)

I hope this will help