if Alfa,Bita are zeroes of the polynomial p(x)=3x²-2x-6, then find Alfa²,Bita²
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Answer:
3x^2 - 2x - 6
α and β are the zeroes of given polynomial (given )
α + β = -b/a
= -(-2)/3
=2/3
α*β = c/a
=-6/3
therefore, α^2, β^2
= ( 2/3 )^2
= 4/9
= (-6/3)^2
= 36/9
so , α^2 = 4/9
and
, β^2 = 36/9
hope it will help you
thanks
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