Question

if alfa,bita,gema is zeros of polynomials ax³+bx²+cx+d so find 1/(alfa)+1/(bita)+1/(gema)=​

Answer 1

Answer:

b/d

Step-by-step explanation:

ax^3 + bx^2 +cx + d

1/(alfa) + 1/(bita) + 1/(gama)

alfa + bita + gama / (alfa) (bita) (gama)

(- b/a) / (-d/a)

b/d