If alfaaz and beeta are the zeros of 2x square +5x - 10 then the value of alfa beeta is
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The roots are shown in the above pic
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2x^2+5x-10
alpha=(-b+rood d)/2a
a=2,b= 5
c= -10
d=b^2-4ac
d=25-4*2*(-10)
d=105
alpha=(-2+root 105)/4
beeta=(-2-root 105)4
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