if alfha & beta are the zeroes of 2x^2-9x+10 from the polynomial whose zeroes are 1/alfha & 1/ beta
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Here a=2, b=-9, c=10 So alpha + beta = -b/a =9/2and alpha.beta =10/2 1/alpha+1/beta =(alpha+beta)/(alpha.bets) =(9/2)/(10/2)=9/10 polynomial is xsq -(1/alpha+1/beta)x +1/alpha. 1/beta. Substitute values: xsq -9/10x+2/10 =10x^2 -9x +2is ans
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