If alfha and beta are the zeros of the quadretic polynomial f(x)= 2xsquare -5x+7, find a polynomial whose zeroes are 2alpha +3beta and 3alpha+2 beta
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If we factorise 2 x square - 5 x - 7
we get alpha = (- 1 )and beta = 7/2
Now,
we have to put the values-
2 alpha + 3 Beta= 17/2 and 3 alpha + 2 Beta = 4
Therefore the required polynomial is 2 x square - 17 x + 8.
we get alpha = (- 1 )and beta = 7/2
Now,
we have to put the values-
2 alpha + 3 Beta= 17/2 and 3 alpha + 2 Beta = 4
Therefore the required polynomial is 2 x square - 17 x + 8.
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