If all face card removed from a 52 cards sac then a card selected find the probability
1) A black card
2) ten or aac
3) A face card or ten
4) A black card or king
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Answered by
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Total number of remaining cards is 40 with 10 cards of each type.
1. P=9/40
2. P=(4+4)/40=1/5
P. S. I am assuming that aac means ace card.
3. P=(4+0)/40=1/10
4. P= (9+0)/40= 9/40
1. P=9/40
2. P=(4+4)/40=1/5
P. S. I am assuming that aac means ace card.
3. P=(4+0)/40=1/10
4. P= (9+0)/40= 9/40
Answered by
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Heya Mate!!!
Total cards = 52
if all face cards are removed = 52 - 12= 40
(1). A black card.
Total black cards= 20
Probability of getting a black = 20/40
= 1/2
(2). total ten= 4
total ace= 4
probability of getting ten or ace= 8/40
= 1/5
(3). Total face card = 0
Total ten= 4
Probability of getting face or ten card= (0+4)/40
= 4/40
= 1/10
(4). Total king = 0
Probability of getting king or black card = (0+20)/40
= 20/40
= 1/2
Hope you like it ....⭐⭐
Total cards = 52
if all face cards are removed = 52 - 12= 40
(1). A black card.
Total black cards= 20
Probability of getting a black = 20/40
= 1/2
(2). total ten= 4
total ace= 4
probability of getting ten or ace= 8/40
= 1/5
(3). Total face card = 0
Total ten= 4
Probability of getting face or ten card= (0+4)/40
= 4/40
= 1/10
(4). Total king = 0
Probability of getting king or black card = (0+20)/40
= 20/40
= 1/2
Hope you like it ....⭐⭐
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