Question

if all objects on the equator of earth feel weightless then the duration of the day will nearly become​

Answer 1

Answer:

1. 84.6min or 1.41h
2. Normal Reaction =0
3. mg-mw^2r=0
4. w=√g/r
5. t=2π÷w=2π√r/g

Answer 2

Duration of Day will be 84.6 Minutes

Explanation:

We know that,

• With increasing revolution rates, the centrifugal force increases, hence reducing the weight of all objects either at or close to the equator.

• Finally, all objects close to equator tend to be weightless, at a particular speed.

For the given case, the acceleration due to gravity at the equator is given by,

$g' = g - R_e\omega^2$

or $\omega = \sqrt {\frac {g}{R_e}}$

= $\sqrt {\frac {9.8}{6.4 \times 10^6}}$

= $1.24 \times 10^-^3 rads^-^1$

In this situation, the period of rotation of the earth about its axis, T or can say length of the day

T = $\frac {2\pi}{\omega}$

= $\frac {2 \times 3.14}{1.24 \times 10^-^3}$

= 5075 seconds or 84.6 min