Question

if all the digits in the number 47623951 are arranged in ascending order from left to right then 2 is added to first four digits of the number and 2 is subtracted to the last four digits of the number. then how many digits are repeating in the number thus formed​

Answer 1

Answer:

We can solve it by finding probabilities

First we have to find out the probability of reading newspaper in the city.

So we have

P(A)=0.6

P(B)=0.4

P(C)=0.3

P(ANB)=0.2

P(ANC)=0.3

P(BNC) =0.1

P(AnBnC)=0.15

as the probability of reading newspaper is calculated by this

P(AUBUC)=P(A)+P(B)+P(C)-P(AnB)-P(AnC) P(BNC) +P(AnBnC)

P(AUBUC) = 0.6+0.4+0.3-0.2-0.3-0.1+0.15

P(AUBUC)=0.85

The probability of reading newspaper is 0.85.

Now the probability of those people do not read newspaper is = 1- P(AUBUC)