if all the exterior angles of a triangle measure twice the measure of one of its opposite interior angles. find the measure of all its interior angles.
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Answered by
18
if interior angle is x then exterior angle will be 2x
As we know total sum of interior angles of a triangle is 180 so interior angles will be x + x +x is 3x=180
so x =180÷3
=60.
thus all its interior angles are of 60°each.
understand dear.
As we know total sum of interior angles of a triangle is 180 so interior angles will be x + x +x is 3x=180
so x =180÷3
=60.
thus all its interior angles are of 60°each.
understand dear.
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Answered by
5
let exterior angle be x,y,z
let interior angle be a,b,c
and let
x=a+b(extior angle property)
y=c+b(exterior angle property )
z=b+a(exterior angle property)
x+c=180°(linear pair angle)
a+b+c=180°(∵x=a+b)
a+a+a=180°(∵a=b=c)
3a=180°
a=180°/3
a=60°
∴a=b=c=60°
let interior angle be a,b,c
and let
x=a+b(extior angle property)
y=c+b(exterior angle property )
z=b+a(exterior angle property)
x+c=180°(linear pair angle)
a+b+c=180°(∵x=a+b)
a+a+a=180°(∵a=b=c)
3a=180°
a=180°/3
a=60°
∴a=b=c=60°
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