Question

if all the oxygen atoms from the mixture of 2 moles H2P2O7, 54 grams H2O and 98 grams H2SO4 are taken and converted into ozone, then the number of moles of ozone gas formed will be what ??​

Answer 1

Answer:

The number of moles of ozone gas formed will be 8 moles.

Explanation:

Moles of $H_2P_2O_7=2 mol$

Number of moles of oxygen atoms =$2mol\times 7=14 mol$

Moles of  water $={54 g}{18 g/mol}=3 mol$

Number of moles of oxygen atom in 3 moles of water = 3 × 2 mo = 6 mol

Moles of $H_2SO_4=\frac{98 g}{98 g/mol}=1 mol$

Number of moles of oxygen atoms in 1 mol of sulfuric acid =1 mol × 4  =4 mol

Total number of moles of oxygen atom = 14 mol+ 6 mol + 4 mol = 24 mol

1 mol of an ozone molecule is made of three oxygen atom. So, 24 mol oxygen atoms will give :

$\frac{1}{3}\times 24=8 moles$ of ozone molecule.

The number of moles of ozone gas formed will be 8 moles.

Answer 2

Answer:

The number of moles of ozone gas formed will be 8 moles.

Explanation:

Moles of

Number of moles of oxygen atoms =

Moles of  water

Number of moles of oxygen atom in 3 moles of water = 3 × 1 mo = 3 mol

Moles of

Number of moles of oxygen atoms in 1 mol of sulfuric acid =1 mol × 4  =4 mol

Total number of moles of oxygen atom = 14 mol+ 6 mol + 4 mol = 21 mol

1 mol of an ozone molecule is made of three oxygen atom. So, 21 mol oxygen atoms will give :

of ozone molecule.

The number of moles of ozone gas formed will be 7 moles.