Question

If all the permutations of the word again are arranged in a dictionary what is the fiftieth word

Answer 1

i) Number of words that can be arranged form the letters 'AAGIN' are:

5!/'2! = 120/2 = 60

ii) When they are arranged as in dictionary,

a) First set of words will start with A, so balance four places 4 letter, AGIN, = 4! = 24

b) Second set starting with G; balance from letters AAIN = 4!/2! = 12

c) Third set starting with I; this also = 4!/2! = 12

So all these total = 24 + 12 + 12 = 48

Hence 49th word will start with N; then comes AAIN

So the word is: 'NAAGI'