If all the sides of a square are increased by 20% its area is increased by
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Answer:44%
Step-by-step explanation:
The area of a square of side s is s^2.
The area of a square of side 1.2s is 1.44s^2.
Therefore, the area is increased by 44%.
CoruscatingGarçon:
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Step-by-step explanation:
Let the side of the square be 'x'.
We know that Area = x^2.
Given that side of a square is increased by 20%.
=> Length of each side = x + 20% of x = 120x/100 = (6/5)x
New area = (6x/5)^2 = (36x^2/25)
Now,
Increase in area = (36x^2/25) - x^2
= (36x^2 - 25x^2)/25
= 11x^2/25
So, the % increase in area = (11x^2/25) * (100/x^2)
= > 1100/25
= > 44.
Therefore, Area is increased by 44%.
Hope this helps!
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