if all vertices of the quadrilateral lie on the same circle then the quadrilateral is cyclic quadrilateral prov fast PLZZZZZZZZZZ
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Given: Cyclic quadrilateral ABCD such that AD = BC
To Prove: AB parallel to CD
Construction: Join BD
Proof: Given that AD = BC
Arc DA = Arc BC
∠2 = ∠1 [Equal chords subtend equal angles at the circumference of the circle]
The angles ∠1and ∠2 are alternate interior angles.
Therefore, AB is parallel to CD
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