If alpa and betaare 0 ofx²+5x+6thenthe value of alpa beta and alpa+beta
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Explanation:
let p(x)=x²+5x+6
alpha and beta are its zeros
p(x) =x²+5x+6
=x²+3x+2x+6
= x(x+3)+2(x+3)
(x+3)(x+2)
therefore , alpha =-3;beta=-2;
alpha +beta=-3+(-2)
=-5
alpha*beta=-3*-2
=6
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