If alpaha and beeta are the zeroes of polynomial 3x2-x-4 find
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3x2 - x - 4
= 3x2 + 3x - 4x - 4
= 3x (x + 1) - 4(x + 1)
= (3x - 4) (x + 1)
Now, to get the zeroes,
(3x - 4) = 0 , (x + 1) = 0
x = 4/3 or x = -1
= 3x2 + 3x - 4x - 4
= 3x (x + 1) - 4(x + 1)
= (3x - 4) (x + 1)
Now, to get the zeroes,
(3x - 4) = 0 , (x + 1) = 0
x = 4/3 or x = -1
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