Question

if alpha=-2 and beta=1/3 then find p(x)?​

Answer 1

Answer:

Answer

We have,

f (x)=x

2

−p(x+1)−c=0

f(x)=x

2

−px−(p+c)=0 (1)

Since,

α,β are the zeroes of the above polynomial.

So,

α+β=p

αβ=−(p+c)

Since,

(α+1)(β+1)=0

αβ+α+β+1=0

−p−c+p+1=0

−c+1=0

c=1

Hence, this is the answer.

Answer 2

Answer:

the formula for p(x)

x²-(alpha +beta)x+ alpha*beta=0

x²-(-2+1/3)x+(-2)*1/3=0

x²+5/3x-2/3=0

3x²+5x-2/3=0

then,

3x²+5x-2=0