Question

If alpha =2, beta =3 are zeroes of polynomial x2-5x +6 then find the polynomial whose zeroes are 1 divide alpha and 1 divide beta

Answer 1

Hii friend,

P(X) = X²-5X+6

Alpha = 2

Betaine = 3

Therefore,

1/Alpha = 1/2

And,

1/Beta = 1/3

Alpha+Beta = 1/2+1/3 = 3+2/6 = 5/6

Alpha×Beta = 1/2×1/3 = 1/6

Therefore,

Quadratic polynomial = X²-(Alpha+Beta)X+ Alpha × Beta. = X²-(5/6)X+1/6

= X²-5X/6 + 1/6 = 0

= 6X² -5X+1 = 0

HENCE,

THE REQUIRED POLYNOMIAL = 6X²-5X+1

HOPE IT WILL HELP YOU.... :-)

Answer 2

6X²+6X-6 is the right answer.

I hope it helps you. mark it best answer!.!.!.![]