if ALPHA = 36, BETA = 26, DELTA=?
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Answered by
3
α+β= -b/a
α+β=36+26
α+β=62
α×β=c/a
α×β=36×26
α×β=936
hence the equation is x²-62x+936=0
therefore, a=1 b=-62 c=936
Δ=b²-4ac
Δ=3844-4×1×936
Δ=100
hence delta(Δ)=100
hope this works.....
α+β=36+26
α+β=62
α×β=c/a
α×β=36×26
α×β=936
hence the equation is x²-62x+936=0
therefore, a=1 b=-62 c=936
Δ=b²-4ac
Δ=3844-4×1×936
Δ=100
hence delta(Δ)=100
hope this works.....
Answered by
5
Answer:
Step-by-step explanation:
ALPHA=36
A+L+P+H+A=1+12+16+8+1=38
but its given 36 means 38-2=36
Similarly,
BETA=26
B+E+T+A=2+5+20+1=28
but its given 26 means 28-2=26
Similarly for DELTA
D+E+L+T+A=42
so answer will be 42-2=40
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