Question

if alpha abd beta are the roots of equation x2+bx+c=0 then the roots of equation cx2-(b2-2c)x+c=0 are Alpha/beta and beta/alpha. Kindly let me know it's solution as soon as possible

Answer 1

Step-by-step explanation:

We know that

alpha+beta=-b/a

alpha*beta=c/a

but if new roots we get

alpha/beta+beta/alpha

={alpha^2+bera^2}/alpha*beta

={(alpha+beta)^2-2alpha*beta}/alpha*beta

={(-b/a)^2-2c/a}/c/a

={b^2/a^2-2c/a}/c/a

=(b^2-2ca)/ca

again,alpha/beta*beta/alpha=1

so quadratic equation=x^2-{(b^2-2ca)/ca}x+1

Hope it helps :)