If alpha & Beta are the zeroes of f(x)=6x^2+x-2.
then find the value of alpha-Beta
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6x²+x-2=0
=>6x²+4x-3x-2=0
=>2x(3x+2)-1(3x+2)=0
=>(3x+2)(2x-1)=0
=>(3x+2)=0=x=-2/3
or,
=>2x-1=0=x=1/2
Hence, x=-2/3 or 1/2
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