Question

If Alpha & Beta are the zeroes of polynomial x^2-7x+10 then form a quadratic polynomial whose zeroes are half the zeroes of given polynomial.​

Answer 1

Answer:

$\alpha + \beta = 7 \\ \alpha \beta = 10 \\ \\ {x}^{2} - ( \frac{ \alpha }{2} + \frac{ \beta }{2} )x + \frac{ \alpha }{2} \times \frac{ \beta }{2} = 0 \\ {x}^{2} - \frac{1}{2} ( \alpha + \beta )x + \frac{ \alpha \beta }{4} = 0 \\ \\ {x}^{2} - \frac{7}{2} x - \frac{10}{4} = 0$

Answer 2

x²-7x + 10

x²-2x-5x + 10

x(x - 2) - 5(x - 2)

(x - 5)(x - 2) = 0

x = 2

X = 5

x² (1+5 ÷ 2)x+10 ÷ 4

x²7x÷2+5÷2

hope is help you dear friend