If alpha & Beta are zeroes of the quadratic polynomial x²-6x+a. find the value of a, If 3alpha + 2beta = 20
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a = -16
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Step-by-step explanation:
α+β = 6
now
3α+2β=20
α+2α+2β=20
α +2(α+β)=20
α+12=20
α=8
now substitute α
α+β=6
β=-2
and the a = constant term / coefficent of x² = α x β
=a = -16
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