Question

if alpha and 1/alpha are the zeroes of polynomial ax2+bx+c then find the value of c​

Answer 1

Answer:

p+q =-b/a (1)

pq = c/a (2)

so, (p-q)2 = p2 + q2 - 2pq

=> (p+q)2 +2pq - 2pg

=> (p+)2 ( from (1) )

=>( -b/a)2 = b2/a2

=> b-a = b/a... Answer!

Step-by-step explanation: