Question

If alpha and 1/alpha are zeroes of 4x2 – 17x + k – 4, find value of k.

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Concept:

If some constant is zero of an expression, then if we put that constant in the expression, then the outcome will be a zero.

Moreover, in a quadratic equation, the product of zeroes is c/a, where c is the constant term, and a is the coefficient of the variable with degree 2.  

Given:

α and 1/α are the zeroes of the given expression

Given expression :-  4x² – 17x + k – 4

Find:

We have to find the value of K.

Solution:

According to the above given concept, in a quadratic equation, the product of zeroes is c/a, where c is the constant term, and a is the coefficient of the variable with degree 2.

4x² – 17x + k – 4

here c = k - 4 and a = 4

product of zeroes = c/a

α × 1/α = ( k - 4 )/4

1 = ( k - 4 )/4

k - 4 = 4

k = 8

Hence, the value of k came out to be 8 after solving.

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