If alpha and β are the zeroes of the quadratic polynomial f(x)=x square—5x+4 find the value of 1/alpha+1/β—2alpha*β.
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Jahnavidax:
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x²-5x+4 =x²-4x-x+4=x(x-4)-1(x-4)=(x-4)(x-1)so alpha is 4 and beta is 1
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