English, asked by Anonymous, 11 months ago

if alpha and beeta are the zeroes of (ax²+bx+c) evaluate a(alpha²/beeta+beeta²/alpha)+b(alpha/beeta+beeta/alpha)

Answers

Answered by deeptarudas2003

2

Answer:The answer is 'b'.

Explanation:

To find better explanation please see the pictures below. I think it's correct.

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