Question

if alpha and beeta are the zeroes of quadratic polynomial p(x)= t^2-4t+3. find the value of alpha^4beeta^3+alpha^3beeta^4​

Answer 1

Explanation:

p(x)= t^2-4t+3

0=t^2-3t-t+3

0=t(t-3)-1(t-3)

0=(t-1)(t-3)

t=1or t=3

alpha=1 and beta=3---1

alpha^4beeta^3+alpha^3beeta^4

=(1^4)(3^3)+(1^3)(3^4)

=27+81

=108