Question

If alpha and beeta are the zeroes of the polynomial p{x}=3x square -12x+15,find the value of alpha and beeta square

Answer 1

Answer:

first simplify the term

3x^2 -12x +15= 3x^2-15x+3x+15

= -3x(x+5) +3(x+5)

=(-3x+3) + (x+5)

this implies alpha = 1 and beeta=5

so alpha +beeta square = (1+5)^2= 6^2= 36