Question

if alpha and beeta are the zeroes of the polynomial x²-5x+k,such that alpha -beeta=1,find the value of k.​

Answer 1

x^2 - 5x + k

alpha - beeta = 1 ------(i)

We know that,

alpha + beeta = -b/a=5 ---(ii)

adding equation (i) and (ii)

alpha - beeta = 1

+ alpha + beeta = 5

=> 2alpha = 6

alpha = 3

Putting the value of alpha in equation (i)

3 - beeta = 1

beeta = 2

We know that,

alpha × beeta = c/a

3 × 2 = k/1

k = 6

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