Question

if alpha and beeta are the zeroes of the polynomial x² +x-6,find the value of 1/ alpha² + 1/ beeta² .​

Answer 1

Answer:

Step-by-step explanation: its boring soooooooo boring pagal

Answer 2

Step-by-step explanation:

let alpha=m

beta= n

for easy notation

m+n =-b/a=-1

mn=c/a=-6

1/m² +1/n²

(m²+n²)/m²n²

(m+n)²=m²+n²+2mn

we get

(-1)²= m²+n²+2(-6)

1=m²+n²-12

m²+n²=13

putting this value in equation we get

13/(-6)²

13/36

thank you