if alpha and beeta are the zeroes of the quadratic polynomial f(x)=x3+13x2+32x+20 if one of it's zeroes is -2
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Given -2 is a zero of polynomial so x+2 is a factor of p(x)
![p(x) = x {3} + 13x {}^{2} + 32x + 20 p(x) = x {3} + 13x {}^{2} + 32x + 20](https://tex.z-dn.net/?f=p%28x%29+%3D+x+%7B3%7D+%2B+13x+%7B%7D%5E%7B2%7D++%2B+32x+%2B+20)
![f(x) = x + 2 f(x) = x + 2](https://tex.z-dn.net/?f=f%28x%29+%3D+x+%2B+2)
on dividing p (x) by f (x)
![(x + 2)(x {}^{2} + 11x + 10) (x + 2)(x {}^{2} + 11x + 10)](https://tex.z-dn.net/?f=%28x+%2B+2%29%28x+%7B%7D%5E%7B2%7D++%2B+11x+%2B+10%29)
![(x + 2)(x {}^{2} + 10x + x + 10) (x + 2)(x {}^{2} + 10x + x + 10)](https://tex.z-dn.net/?f=%28x+%2B+2%29%28x+%7B%7D%5E%7B2%7D++%2B+10x+%2B+x+%2B+10%29)
on dividing p (x) by f (x)
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