if alpha and beeta are the zeroes of the quadratic polynomial f(x)=3x2-6x+4.find the value of 1)alpha square beeta+beeta square alpha 2)alpha/beeta+beeta/alpha+2(1/alpha+1/beeta)+3(alpha×beeta
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The answer for first
1) 3/8
The answer for second
2) 8/3
1) 3/8
The answer for second
2) 8/3
aks187:
i want the full answer
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