Question

If alpha and beeta are the zeroes of the quadratic polynomial f(x)=ax^2+bx+c, then evaluate alpha square + beeta square

Answer 1

$here \: is \: your \: answer \: mate$

$\alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = \frac{c}{a} \\ { \alpha }^{2} + { \beta }^{2} = {( \frac{ - b}{a} )}^{2} + 2 \times \frac{c}{a} \\ = \frac{ - b}{a} + \frac{2c}{a} \\ = \frac{ - b + 2c}{a}$

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