if alpha and beeta are the zeroes of the2x²+5x-10 then the value of alpha beeta is
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given : α and β are zeroes of polynomial .
α + β = - b / a = - ( - 5 ) / 2 ...............(i)
α.β = c / a = 7 / 2 ...............(ii)
i think zeroes of the polynomial will be there .
so if zero of the polynomial are assumed to be [ 2α + 3 β ] and [3 α + 2 β ]
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Product of zeroes = c/a
=10/2
=5
=10/2
=5
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