Question

if alpha and beeta are the zeroes of x²-5x+4 find the value of alpha ams and beeta​

Answer 1

Step-by-step explanation:

x^2-5x+4=0

x^2-1x-4x+4=0

x(x-1)-4(x-1)=0

(x-1)(x-4)=0

x=1 or 4

So alpha and beta are 1 and 4 respectively.