Question

if alpha and beeta are the zeros of a quadratic polynomial x^2-x-2, then find the value of 1/alpha -1/beeta​

Answer 1

Heya mate!!!

Gud Morning....

Here is ur answer:

• The quadratic polynomial is
• ${x}^{2} - x - 2 = 0$
• Let's find the zeoes of this quadratic polynomial by splitting the middle term or any other method.

${x}^{2} + x - 2x - 2 = 0$

$x(x + 1) - 2(x + 1) = 0$

$(x + 1)(x - 2) = 0$

$x = - 1 \: or \: 2$

• We have got the value of alpha and beta. Let's substitute it to find the required answer.
• $\alpha = - 1 \: \: \: \: \: \beta = 2$

$\frac{1}{ \alpha } - \frac{1}{ \beta } = - 1- \frac{ 1}{2}$

$= \frac{ - 2 - 1}{2} = \frac{ - 3}{2}$

Hope this hlps uuu...

Be Brainly!!!!

Answer 2

Answer:

here is your answer

Step-by-step explanation:

hope u like answer