Question

if alpha and beeta are the zeros of of a quadratic polynomial x^2-x-2, then find the value of 1/alpha -1/beeta​

Answer 1

Answer:

Step-by-step explanation:

α+β = 1

αβ = -2

x²-x-2

x²-2x-x-2

x(x-2)+1(x-2)

(x+1)(x-2)

Zeros are -1,2

α= -1 ,β=2

1/α - 1β

1/-1 - 1/2

-1 - 1/2

= -3/2