Question

if Alpha and beeta are the zeros of the quadratic polynomial 2x²-4x+5, find the value of alpha²/2*beeta+beeta2/2*alpha​

Answer 1

Answer:

bhghhsh4uruehrhrdbbd 4nje

Answer 2

Answer:

2x² - 4x +5 =0α+β = -(-4/2) = 2αβ = 5/2i)α² +β² = (α+β)² - 2αβ = (2)²- 2×(5/2) = 4-5 = -1ii)(α-β)² = (α+β)² - 4αβ =(2)² - 4×(5/2) = 4 - 10 = -6

Step-by-step explanation:

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