Question

If alpha and beeta are two zeroes of x^2-7x+12 then find

Answer 1

x2 - 7x + 12

facterisation

x2 - 3x - 4x + 12 = 0

x(x-3) - 4(x-3) = 0

(x-3) (x-4) = 0

(x-3) =0 , (x-4) = 0

x=3 , x = 4

The zeroes are {3,4}

Now alpha = 3

beeta = 4 (or) viseversa

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